python socket pętla

Question

Witam

Napisałem prosty socket w pythonie, nie wiej jak doprowadzić do sytuacji aby ten socket działał w pętli.

#!/usr/bin/env python3

import socket

HOST = '127.0.0.1'  # Standard loopback interface address (localhost)
PORT = 2121        # Port to listen on (non-privileged ports are > 1023)

ppp = ''


def stream(stream):
    global ppp
    ppp += stream

    if ppp.find("policy_context=") >= 0:

        print(ppp+"\n\n---1\n")


with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
    s.bind((HOST, PORT))
    s.listen()
    conn, addr = s.accept()
    while True:
        print('Connected by', addr)
        while True:
            data = conn.recv(1024)
            if not data:
                break
            conn.sendall(data)
            stream(data.decode('utf-8'))
                #print(ppp)
                #conn.sendall(data)

skryp po uruchomieniu czeka do momentu połączenia klienta, gdy klient zostanie połączony skrypt spamuje:

Connected by ('127.0.0.1', 44254)
Connected by ('127.0.0.1', 44254)
Connected by ('127.0.0.1', 44254)
Connected by ('127.0.0.1', 44254)
Connected by ('127.0.0.1', 44254)

...