Problem z kodem php

Question

Coś tu poszło nie tak:

Warning: Undefined array key "my_file" in C:\xampp\htdocs\Thales\upload.php on line 2

Warning: Trying to access array offset on value of type null in C:\xampp\htdocs\Thales\upload.php on line 2

 Jakieś pomysły ?

<form name="form" method="post" action="upload.php" enctype="multipart/form-data" >
<input type="file" name="my_file" /><br /><br />
<input type="submit" name="submit" value="Upload"/>
</form>

UPLOAD.PHP:
<?php
if (($_FILES['my_file']['name']!="")){
 $target_dir = "Pliki/";
 $file = $_FILES['my_file']['name'];
 $path = pathinfo($file);
 $filename = $path['filename'];
 $ext = $path['extension'];
 $temp_name = $_FILES['my_file']['tmp_name'];
 $path_filename_ext = $target_dir.$filename.".".$ext;
 
// Check if file already exists
if (file_exists($path_filename_ext)) {
 echo "Sorry, file already exists.";
 }else{
 move_uploaded_file($temp_name,$path_filename_ext);
 echo "Congratulations! File Uploaded Successfully.";
 }
}
?>

 

Comments

możesz dać na początek kodu var_dump($_FILES); i dać co ci wyskakuje?

---

array(1) { ["file"]=> array(5) { ["name"]=> string(7) "2.2.pdf" ["type"]=> string(15) "application/pdf" ["tmp_name"]=> string(24) "C:\xampp\tmp\phpEF82.tmp" ["error"]=> int(0) ["size"]=> int(154487065) } }
Warning: Undefined array key "my_file" in C:\xampp\htdocs\Thales\upload.php on line 3

Warning: Trying to access array offset on value of type null in C:\xampp\htdocs\Thales\upload.php on line 3

---

Plik upload.php otrzymuje nazwę file nie my_file, spróbuj zmienić nazwę w inputcie na np "myFile". Ale aktualnie jeśli chcesz aby to działało pozamieniaj $_FILES['my_file'] na $_FILES['file']. Jednak zamiast wpisywać != "" użyj funkcji isset albo !empty

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O matko bosko działa !!! DZiękuję ♥♥♥

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Dobra, działało przez chwilę:

Warning: Undefined array key "file" in C:\xampp\htdocs\Thales\upload.php on line 2

Warning: Trying to access array offset on value of type null in C:\xampp\htdocs\Thales\upload.php on line 2

---

możesz pokazać aktualnie twój kod oraz input z file?

Answer 1

Wygląda na to że nie są zadeklarowane takie pola w tablicy (zawierają null). Pojawia się to gdy wchodzisz na upload.php?

Takie rzeczy dobrze sprawdza się funkcją isset() wystarczy że podmienisz na nią warunek w if'ie

Answer 2

Spróbuj w ten sposób:

<form name="form" method="post" action="upload.php" enctype="multipart/form-data" >
  <input type="file" name="my_file" /><br /><br />
  <input type="submit" name="submit" value="Upload"/>
</form>

<?php
  if ($_SERVER['REQUEST_METHOD'] == 'POST' && !empty($_FILES['my_file']['name'])) {
    $target_dir = 'Pliki/';
    $temp_name = $_FILES['my_file']['tmp_name'];
    $path_filename = $target_dir.$_FILES['my_file']['name'];
  
    // Check if file already exists
    if (file_exists($path_filename)) {
      echo 'Sorry, file already exists.';
    } else {
      move_uploaded_file($temp_name,$path_filename);
      echo 'Congratulations! File Uploaded Successfully.';
    }
  }
?>

 

zamiast <br> w kodzie

<style>
  input {
    display: block;
  }
  input[type="submit"] {
    margin-top: 1em;
  }
</style>

<form name="form" method="post" action="upload.php" enctype="multipart/form-data" >
  <input type="file" name="my_file" />
  <input type="submit" name="submit" value="Upload"/>
</form>

<?php
  if ($_SERVER['REQUEST_METHOD'] == 'POST' && !empty($_FILES['my_file']['name'])) {
    $target_dir = 'Pliki/';
    $temp_name = $_FILES['my_file']['tmp_name'];
    $path_filename = $target_dir.$_FILES['my_file']['name'];
  
    // Check if file already exists
    if (file_exists($path_filename)) {
      echo 'Sorry, file already exists.';
    } else {
      move_uploaded_file($temp_name,$path_filename);
      echo 'Congratulations! File Uploaded Successfully.';
    }
  }
?>